C Program to Check Leap Year

In this program the user gives a number that is a leap year then the program will display the leap year. And if it is not a leap year, it will print Not, Leap Year!

We all know that there are 365 days in a calendar year. But a year takes exactly 365.2425 days. For this, after 4 years, the calendar has to be readjusted by one day. This is called a leap year.

Leap year, we will use C programming language through this program to check whether the user's given year is a leap year. Some examples of leap years are:

1997 is not leap year!

1996 is leap year!

2024 is leap year!

#include<stdio.h>
int main(){
    int year;
    printf("Enter Year: ");
    scanf("%d",&year);

    if((year%4==0) || (year%400==0) && (year%100 !=0)){
        printf("Yes, Leap year! \n");
    }

    else
      printf("Not, Leap year! \n");


return 0;
}

Output

Enter Year: 1996
Yes, Leap year!